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39d^2-23d=0
a = 39; b = -23; c = 0;
Δ = b2-4ac
Δ = -232-4·39·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-23}{2*39}=\frac{0}{78} =0 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+23}{2*39}=\frac{46}{78} =23/39 $
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